Running PHP Script from terminal with parameters

I try to get parameters and run php script from terminal. If one of the parameters is not exists, I want to thrown an exception. I used getopt function. But I could not figure out how to thrown exception. And when I call the script

php myscript.php --file: file1.csv --unique-combinations: file2.csv
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it's not working.

<?php
$files = getopt("file:unique-combinations:");

if(!files["file"]) {
    echo "Please provide a CSV file with parameter file";
} else if(!files["unique-combinations"]) {
    echo "Please provide a file name to save unique combinations with parameter unique-combinations";
} else {
    $datas = array_count_values(file(files["file"]));
    $fp = fopen(files["unique-combinations"], 'w');

    foreach($datas as $data => $value) {
        fputcsv($fp, $data);
    }
    fclose($fp);
}
?>
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Could someone help me to figure out this.

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