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Good morning, I have a string in which there are breaks represented as<p>----</p>. The number of dash is often different. Sometimes there are 4, sometimes 5, etc.
Something like this:
Lorem ipsum
<p>------</p>
Lorem Ipsum
<p>
I would like to write a php preg_replace command to make them all uniform and identical.
This is what I developed, but it doesn't work. Where is the error?
{-code-3}
Moreover there is something more precise rather than{-code-4} to match only spaces and dashes.
EDIT 1: Thanks to the team in the answer section, I correct the function like this:
{-code-5}
This works fine as long as long the text doesn't have a break between the last dash and{-code-6}. How can I identify the dashed, spaces and also capture the{-code-7}?
Example:<p>----- {-code-7}{-code-6}
You don't really need the 3 capture groups. You can match zero or more horizontal whitspace chars using{{-code-3}code{-code-3}1} and replace that with the fixed replacement of{{-code-3}code{-code-3}2}
Example, where as in your code there is always a{-code-3} at the start and end:
$item = <<<DATA
Lorem ipsum
<p>{-code-3}{-code-3}{-code-3}{-code-3}{-code-3}{-code-3}</p>
Lorem Ipsum
<p>{-code-3}{-code-3}{-code-3}{-code-3}{-code-3}{-code-3}{-code-3}{-code-3}{-code-3}{-code-3}{-code-3}{-code-3}{-code-3}{-code-3}{-code-3}{-code-3}</p>
Lorem Ipsum
<p>{-code-3}{-code-3}{-code-3}{-code-3}{-code-3}{-code-3}{-code-3}{-code-3}{-code-3} {-code-3}{-code-3}{-code-3}{-code-3}{-code-3}</p>
DATA;
$search = "~<p>{-code-3}{{-code-3}code{-code-3}1}{-code-3}</p>~";
$replace = "{{-code-3}code{-code-3}2}";
$item = preg_replace($search, $replace, $item);
echo $item;
Output
Lorem ipsum
{{-code-3}code{-code-3}2}
Lorem Ipsum
{{-code-3}code{-code-3}2}
Lorem Ipsum
{{-code-3}code{-code-3}2}
You may try finding the pattern and then replace with however many dashes you want, e.g.{-code-2}:
$input = "Lorem ipsum \n<p>------</p>\nLorem Ipsum \n<p> This prints:
Lorem ipsum
<p>-----</p>
Lorem Ipsum
<p>-----</p>
Lorem Ipsum
<p>-----</p>
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