If there is other HTML content elsewhere in your PHP script then this will also be outputted as it normally is, except in this case it will become part of the downloaded file. If you don't want that to happen then you have to stop your script with anexit();
command after you have output the content you actually want. In your script, it looks like you can probably do this just after the call to the function. (But if you have already output some HTML before this, you'll need to alter your script more substantially.)
N.B. I'm surprised you aren't getting a warning about headers being already sent? That normally happens if you try to set headers after you've already echoed some content. Check your log files. Normally you are supposed to output the headers first.
Also, unless you are wanting to keep it for some other purpose, there is no use in saving anything tourlscan.txt
- it is not playing any part in your download process. And it would get overwritten every time this script is executed anyway. The headers will cause the browser to treat the output contents (i.e. anything which the PHP script sends to the regular output) as a text file - but this is not the same file as the text file on your server's disk, and its contents can be different.
You happen to be outputting similar content (viaecho" $formatted_url<br>";
) as you are adding to the urlscan file (viafwrite($fh, $formatted_url."\n");
) and I think this may be confusing you into thinking that you're outputting the contents ofurlscan.txt
, but you aren't - your PHP headers are telling the browser to treat the output of your script (which would normally just go onto the browser window as a HTML page) as a file - but it's a) a new file, and b) actually isn't a file at all until it reaches the browser, it's just a response to a HTTP request. The browser turns it into a file on the client machine because of how it interprets the headers.
Another thing: the content you output needs to be in text format, not HTML, so you need to change the<br>
in yourecho
to a\n
.
Lastly, you're outputting the content-type header twice, which is nonsense. A HTTP request or response can only have one content type. In this case, text/plain is the valid MIME type, the other one is not real.
Taking into account all of the above, your code would probably be better written as:
function get_m3u8_video_segment($url, $portnum=80, $from, $to)
{
//header download
$file_name="urlscan.txt";
header("Content-Disposition: attachment; filename=\"" . $file_name . "\"");
header('Expires: 0');
header('Cache-Control: must-revalidate');
header('Pragma: public');
header("Content-Type: text/plain");
for ($x = $from; $x <= $to; $x++)
{
$formatted_url="{$url}:{$portnum}/s-{$x}.m3u8";
$contents = get_web_page( $formatted_url );
if ((strpos($contents, 'not found') !== false)||(strpos($contents, 'EXTM3U') !== false))
{
echo" $formatted_url\n";
}
}
}
get_m3u8_video_segment($url, $portnum, $from, $to);
exit();
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PHP (from the English Hypertext Preprocessor - hypertext preprocessor) is a scripting programming language for developing web applications. Supported by most hosting providers, it is one of the most popular tools for creating dynamic websites.
The PHP scripting language has gained wide popularity due to its processing speed, simplicity, cross-platform, functionality and distribution of source codes under its own license.
https://www.php.net/
HTML (English "hyper text markup language" - hypertext markup language) is a special markup language that is used to create sites on the Internet.
Browsers understand html perfectly and can interpret it in an understandable way. In general, any page on the site is html-code, which the browser translates into a user-friendly form. By the way, the code of any page is available to everyone.
https://www.w3.org/html/
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