php - update page - update all records with the same data

    <!-- Update Form -->
    <form  style = "font-size : 30px">
   

      <input type="text" id="lab_name" class="fadeIn second" name="lab_name" placeholder="Laboratory Name" required>
      <input type="text" id="test_price" class="fadeIn second" name="test_price" placeholder="Test Price" required>
      <input type="text" id="lat" class="fadeIn second" name="lat" placeholder="Lat" required>
      <input type="text" id="lon" class="fadeIn second" name="lon" placeholder="Lon" required>
      <div class="dropdown">
            <select name="lab_city" class="dropdown" required>
                <option value="">--- Select City---</option>
                <option  value="Khartoum">Dubai</option>
                 <option  value="Bahri">Bahri</option>
                 <option value="Omdurman">Paris</option>
               </select>

               <input type="file" name="image" id="image" required>
         
      </div>




      <input type="submit" id="submit" class="fadeIn fourth" value="Update">

   

  </div>
</div>

</form>
        

<section>
  
<?php
  $servername = "localhost";
$username = "root";
$password = "";
$dbname = "covidsd";


// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}


$lab_id = $_GET['lab_id'];
$lab_name= mysqli_real_escape_string($link, $_REQUEST['lab_name']);


  $lab_city = mysqli_real_escape_string($link, $_REQUEST['lab_city']);

  $test_price= mysqli_real_escape_string($link, $_REQUEST['test_price']);
  $lat= mysqli_real_escape_string($link, $_REQUEST['lat']);
  $lon= mysqli_real_escape_string($link, $_REQUEST['lon']);
  $image= mysqli_real_escape_string($link, $_REQUEST['image']);



//$ServerURL = "http://192.168.43.236/AndroidUploadImage/$ImagePath";

  $sql = "UPDATE laboratories SET lab_name ='$lab_name',lab_city ='$lab_city', test_price= '$test_price', lat='$lat',  lon= '$lon', image= '$image' ". "WHERE lab_id='$lab_id' ";

if(mysqli_query($link, $sql)){

    $message = "Laboratory has been updated successfully";
 echo "<script type='text/javascript'>alert('$message');</script>";
  } else{

      echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);

  }

   

  // close connection

  mysqli_close($link);

?>
 
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I tried many solutions but not working