Based on this result from an API
"name": {
"common": "Italy",
"official": "Italian Republic",
"nativeName": {
"ita": {
"official": "Repubblica italiana",
"common": "Italia"
}
}
},
Let's suppose i always want the "common" name but, depending on the country the "key" will vary (now it's "ita" but it could be anything)
What is the cleanest way to always get the "common" value independently of the key name above? (so a dynamic function that always get the common value)
With fixed structures you can do that:
$arr = json_decode('{"name": {
"common": "Italy",
"official": "Italian Republic",
"nativeName": {
"ita": {
"official": "Repubblica italiana",
"common": "Italia"
}
}
}}',true);
$country = key($arr['name']['nativeName']); //ita
$common = $arr['name']['nativeName'][$country]['common']; //Italia
echo '$country = '.$country.', $common = '.$common;
Demo: https://3v4l.org/W4sqI
You could iterate over that part of the data structure like this to get both the key and the value ofcommon
$json = '{
"name": {
"common": "Italy",
"official": "Italian Republic",
"nativeName": {
"ita": {
"official": "Repubblica italiana",
"common": "Italia"
}
}
}
}';
foreach (json_decode($json)->name->nativeName as $key => $native){
echo "Key = $key, common = {$native->common}";
}
RESULT
Key = ita, common = Italia
You can useget_mangled_object_vars()
withkey()
if you have just onenativeName
like:
$a = json_decode('{"name": {
"common": "Italy",
"official": "Italian Republic",
"nativeName": {
"ita": {
"official": "Repubblica italiana",
"common": "Italia"
}
}
}}');
print_r(key(get_mangled_object_vars($a->name->nativeName))); // ita
Reference:
Or you can useArrayObject
combine withgetIterator()
andkey()
like:
$a = json_decode('{"name": {
"common": "Italy",
"official": "Italian Republic",
"nativeName": {
"ita": {
"official": "Repubblica italiana",
"common": "Italia"
}
}
}}');
$arrayobject = new ArrayObject($a->name->nativeName);
$iterator = $arrayobject->getIterator();
echo $iterator->key(); //ita
Reference:
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