By returning an
<img> tag, you are basically echo'ing an
<img> tag into an
src attribute which effectively looks like this:
<img src="<img src="data:image/jpeg;base64">">
showImage script, there's no reason to base64 encode anything, that's only need when you are using a text-based transport like HTML. Since you are transporting over HTTP which supports binary, you can instead just send the file. There's a couple of ways, but the easiest is:
echo file_get_contents($image); exit;
Another option that is a little more performant for larger files is:
If you want to get a little fancier, you can also output the MIME for the file:
header('Content-Type: ' . mime_content_type($image)); readfile($image); exit;
I should also point out that passing filenames as parameters without sanitization and validation is a big security problem that can lead to path traversal problems. At a minimum, I'd call
basename() on the supplied parameter, but you should probably look into your specific setup to see what could or couldn't go wrong.
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PHP (from the English Hypertext Preprocessor - hypertext preprocessor) is a scripting programming language for developing web applications. Supported by most hosting providers, it is one of the most popular tools for creating dynamic websites.
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