php - How to select several array elements and check if they are equal to variable

Solution:

Yes you can usearray_keys function. It will return all the indices that match the value you want to look for. Then you can usearray_intersect function to check whether those indices match your indices you want to look for.

$var = 50;
$indices = [0, 2];
$keys = array_keys($fevArr, $var);
$matches = array_intersect($indices, $keys);

if(count($matches) > 0) {
   ...
}
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Solution:

You can usein_array($var, $fevArray) (see documentation) in yourif statement.

Solution:

You can use eitherarray_search (link) which returns the key of the first match andfalse if no match found OR you can usein_array (link) method which will just check the existance.

Solution:

in_array() is not consistent just like this

you can use the following code, I got it here

function contains($str, array $arr)
{
    foreach($arr as $a) {
        if (stripos($str,$a) !== false) return true;
    }
    return false;
}
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and you can apply it as:

if (contains($var, $fevArr) {
 echo "It is";
}
else {
 echo "It is not";
}
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Solution:

<?php
    function contains_at_keys($haystack, $needle, $keys){
        //get all keys matching needle
        $matching_keys = array_keys($haystack, $needle);
        
        //return if these keys contain one or more of the keys to search
        return(sizeof(array_intersect($matching_keys, $keys)) > 0);
    }
    
    
    $str = "100, 2000, 3000, 50, 300, 50, 200";
    $fevArr = explode(",", $str);
    $var = 50;
    
    $keys = [3, 5];
    
    
    if(contains_at_keys($fevArr, $var, $keys)){
        echo("It is");
    } else {
        echo("It is not");
    }
?>
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