I am using Bootstrap cards with MySQL/PHP to echo data from a database/ table.
I have a column in the database "Favourite", this field is either empty or contains a path to an image.
If the corresponding database field is empty for a particular record, I would like to echo nothing. Right now, it is echoing a broken icon (probably because I'm using the img tag?).
Here is the first part of the code:
<?php
include_once("conn.php");
$sql = "SELECT * FROM table ORDER BY id ASC";
$result = mysqli_query($conn, $sql);
if(mysqli_num_rows($result) > 0)
{
while($row = mysqli_fetch_array($result))
{
?>
Here is the echo function;
<img alt="Favourite" title="Favourite" src="http://localhost/Test/Images/Icons/<?php echo $row["Favourite"]; ?>" width="12.5%" height="12.5%"/>
I'm an amateur.. so would ideally like to make the solution as simple as possible.
Thanks in advance!
<?php if(!empty($row["Favourite"])) { ?>
<img alt="Favourite" title="Favourite" src="http://localhost/Test/Images/Icons/<?php echo $row["Favourite"]; ?>" width="12.5%" height="12.5%"/>
<?php } ?>
More on empty function: https://www.php.net/manual/en/function.empty.php
This code will work, if favorite will not empty
<?php
include_once("conn.php");
$sql = "SELECT * FROM table ORDER BY id ASC";
$result = mysqli_query($conn, $sql);
if(mysqli_num_rows($result) > 0)
{
while($row = mysqli_fetch_array($result))
{
$favourite = $row["Favourite"];
}
}
if(!empty($favourite)) {
echo '<img alt="Favourite" title="Favourite" src="http://localhost/Test/Images/Icons/"'.$favourite.'width="12.5%" height="12.5%"/>';
}
else{
//rest of code
}
?>
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