php - Single result from database using mysqli

I am trying to use mySQLi for the first time. I have done it in the case of loop. Loop results are showing but I am stuck when I try to show a single record. Here is loop code that is working.

<?php
// Connect To DB
$hostname="localhost";
$database="mydbname";
$username="root";
$password="";

$conn = mysqli_connect($hostname, $username, $password, $database);
?>

<?php
$query = "SELECT ssfullname, ssemail FROM userss ORDER BY ssid";
$result = mysqli_query($conn, $query);
$num_results = mysqli_num_rows($result);
?>

<?php
/*Loop through each row and display records */
for($i=0; $i<$num_results; $i++) {
$row = mysqli_fetch_assoc($result);
?>

Name: <?php print $row['ssfullname']; ?>
<br />
Email: <?php print $row['ssemail']; ?>
<br /><br />

<?php 
// end loop
} 
?>

How do I show a single record, any record, name, or email, from the first row or whatever, just a single record, how would I do that? In a single record case, consider all the above loop part removed and let's show any single record without a loop.

Solution:

When just a single result is needed, then no loop should be used. Just fetch the row right away.

• In case you need to fetch the entire row into associative array:

    $row = $result->fetch_assoc();
  

• in case you need just a single value

    $row = $result->fetch_row();
    $value = $row[0] ?? false;
  

The last example will return the first column from the first returned row, or false if no row was returned. It can be also shortened to a single line,

$value = $result->fetch_row()[0] ?? false;

Below are complete examples for different use cases

Variables to be used in the query

When variables are to be used in the query, then a prepared statement must be used. For example, given we have a variable $id:

$query = "SELECT ssfullname, ssemail FROM userss WHERE id=?";
$stmt = $conn->prepare($query);
$stmt->bind_param("s", $id);
$stmt->execute();
$result = $stmt->get_result();
$row = $result->fetch_assoc();

// in case you need just a single value
$query = "SELECT count(*) FROM userss WHERE id=?";
$stmt = $conn->prepare($query);
$stmt->bind_param("s", $id);
$stmt->execute();
$result = $stmt->get_result();
$value = $result->fetch_row()[0] ?? false;

The detailed explanation of the above process can be found in my article. As to why you must follow it is explained in this famous question

No variables in the query

In your case, where no variables to be used in the query, you can use the query() method:

$query = "SELECT ssfullname, ssemail FROM userss ORDER BY ssid";
$result = $conn->query($query);
// in case you need an array
$row = $result->fetch_assoc();
// OR in case you need just a single value
$value = $result->fetch_row()[0] ?? false;

By the way, although using raw API while learning is okay, consider using some database abstraction library or at least a helper function in the future:

// using a helper function
$sql = "SELECT email FROM users WHERE id=?";
$value = prepared_select($conn, $sql, [$id])->fetch_row[0] ?? false;

// using a database helper class
$email = $db->getCol("SELECT email FROM users WHERE id=?", [$id]);

As you can see, although a helper function can reduce the amount of code, a class' method could encapsulate all the repetitive code inside, making you to write only meaningful parts - the query, the input parameters and the desired result format (in the form of the method's name).

Solution:

Use mysqli_fetch_row(). Try this,

$query = "SELECT ssfullname, ssemail FROM userss WHERE user_id = ".$user_id;
$result = mysqli_query($conn, $query);
$row   = mysqli_fetch_row($result);

$ssfullname = $row['ssfullname'];
$ssemail    = $row['ssemail'];

Solution:

If you assume just one result you could do this as in Edwin suggested by using specific users id.

$someUserId = 'abc123';

$stmt = $mysqli->prepare("SELECT ssfullname, ssemail FROM userss WHERE user_id = ?");
$stmt->bind_param('s', $someUserId);

$stmt->execute();

$stmt->bind_result($ssfullname, $ssemail);
$stmt->store_result();
$stmt->fetch();

ChromePhp::log($ssfullname, $ssemail); //log result in chrome if ChromePhp is used.

OR as "Your Common Sense" which selects just one user.

$stmt = $mysqli->prepare("SELECT ssfullname, ssemail FROM userss ORDER BY ssid LIMIT 1");

$stmt->execute();
$stmt->bind_result($ssfullname, $ssemail);
$stmt->store_result();
$stmt->fetch();

Nothing really different from the above except for PHP v.5

Solution:

Instead of using $row = $query->fetch(); try to use:

$result = $query->get_result();
$row=$result->fetch_assoc();

every time you can check if you get data from mysql tables by displaying them using:

var_export( $row['put your column name here'] );

Solution:

The first answer will do the job but in this case you don't need to loop the result.

$row = $result->fetch_row();

Just echo the column

  echo   $row['column']; 

This should do the trick

Solution:

As of PHP 8.1, mysqli_result::fetch_column() is available

You can use mysqli_result::fetch_column() to fetch a single scalar value from the result set.

The new method accepts 0-based position of the column you want to read. The default value is 0.

$query = "SELECT ssfullname, ssemail FROM userss WHERE ud=?";
$stmt = $conn->prepare($query);
$stmt->execute([$id])
$result = $stmt->get_result();
$ssemail = $result->fetch_column(1);

Beware that this method will move the internal pointer to the next row, just like the other fetch_* methods do. When it reaches the end, it will return false. Therefore, in the above example, you would be better off using fetch_assoc() to fetch the entire row into an array.

It can also be used with mysqli::query() for SQL statements without parameters.

$query = "SELECT count(*) FROM userss";
$count = $conn->query($query)->fetch_column();