php - Check what part of an IF statement is false/true when using logical operators

one text

Solution:

There's no good way. In the case you describe PHP will not evaluate all the content of the parentheses.

In case empty($a) is true, php will not evaluate empty($b). Because the OR will be true anyway.

You can do the following test:

$a = 1; $b = 0;
if($a || $c) print "2";

This should be show PHP Notice: Undefined variable: c.. But instead it print 2

The best is to evaluate separately

try{
    if(empty($a)) throw new \Exception('$a is empty');
    if(empty($b)) throw new \Exception('$b is empty');
} catch (\Exception $e) {
    print($e->getMessage());
}